Find the equations of the altitudes of a ΔABC whose vertices are A (1, 4), B (-3, 2) and C (-5, -3).
Find the equations of the altitudes of a ΔABC whose vertices are A (1, 4), B (-3, 2) and C (-5, -3).

According to ques,:

The vertices of ∆ABC are A (1, 4), B (− 3, 2) and C (− 5, − 3).

Now let us find the slopes of ∆ABC.

    \[Slope\text{ }of\text{ }AB\text{ }=\text{ }\left[ \left( 2\text{ }\text{ }4 \right)\text{ }/\text{ }\left( -3-1 \right) \right]~\]

    \[=\text{ }{\scriptscriptstyle 1\!/\!{ }_2}\]

And,

    \[Slope\text{ }of\text{ }BC\text{ }=\text{ }\left[ \left( -3\text{ }\text{ }2 \right)\text{ }/\text{ }\left( -5+3 \right) \right]~\]

    \[=\text{ }5/2\text{ }~\]

And again,

    \[Slope\text{ }of\text{ }CA\text{ }=\text{ }\left[ \left( 4\text{ }+\text{ }3 \right)\text{ }/\text{ }\left( 1\text{ }+\text{ }5 \right) \right]~\]

    \[=\text{ }7/6~\]

Thus, we have:

    \[Slope\text{ }of\text{ }CF\text{ }=\text{ }-2\]

    \[Slope\text{ }of\text{ }AD\text{ }=\text{ }-2/5~\]

And,

    \[Slope\text{ }of\text{ }BE\text{ }=\text{ }-6/7~\]

Hence,

Equation of CF is:

    \[y\text{ }+\text{ }3\text{ }=\text{ }-2\left( x\text{ }+\text{ }5 \right)\]

    \[y\text{ }+\text{ }3\text{ }=\text{ }-2x\text{ }\text{ }10\]

or,

    \[2x\text{ }+\text{ }y\text{ }+\text{ }13\text{ }=\text{ }0\]

Equation of AD is:

    \[y\text{ }\text{ }4\text{ }=\text{ }\left( -2/5 \right)\text{ }\left( x\text{ }\text{ }1 \right)\]

    \[5y\text{ }\text{ }20\text{ }=\text{ }-2x\text{ }+\text{ }2\]

Or,

    \[2x\text{ }+\text{ }5y\text{ }\text{ }22\text{ }=\text{ }0\]

Equation of BE is:

    \[y\text{ }\text{ }2\text{ }=\text{ }\left( -6/7 \right)\text{ }\left( x\text{ }+\text{ }3 \right)\]

    \[7y\text{ }\text{ }14\text{ }=\text{ }-6x\text{ }\text{ }18\]

Or,

    \[6x\text{ }+\text{ }7y\text{ }+\text{ }4\text{ }=\text{ }0\]

∴ The required equations are:

    \[~2x\text{ }+\text{ }y\text{ }+\text{ }13\text{ }=\text{ }0,\]

    \[2x\text{ }+\text{ }5y\text{ }\text{ }22\text{ }=\text{ }0,\]

And

    \[6x\text{ }+\text{ }7y\text{ }+\text{ }4\text{ }=\text{ }0.\]