Find the number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated. How many of these will be even?
Find the number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated. How many of these will be even?

Total number of digits possible for choosing

    \[=\text{ }5\]

Number of places for which a digit has to be taken

    \[=\text{ }5=4\]

As there is no repetition allowed,

⇒ Number of permutations =
NCERT Solutions for Class 11 Maths Chapter 7 Permutations and Combinations Image 10

The number will be even when 2 and 4 are at one’s place.

The possibility of (2, 4) at one’s place

    \[=~2/5\text{ }=\text{ }0.4\]

Total number of even number

    \[=\text{ }120\text{ }\times \text{ }0.4\text{ }=\text{ }48.\]