(i) Let
The range of principal value of cot-1 is (0, π) and cot (5 π/6) = – √3
=> the principal value of cot-1 (- √3) is 5π/6
(ii) Let
The range of principal value of cot-1 is (0, π) and
=> the principal value of cot-1 (√3) is π/6
(i) Let
The range of principal value of cot-1 is (0, π) and cot (5 π/6) = – √3
=> the principal value of cot-1 (- √3) is 5π/6
(ii) Let
The range of principal value of cot-1 is (0, π) and
=> the principal value of cot-1 (√3) is π/6