Find the values of a and b, when:
(i) (a + 3, b –2) = (5, 1)
(ii) (a + b, 2b – 3) = (4, –5)
Find the values of a and b, when:
(i) (a + 3, b –2) = (5, 1)
(ii) (a + b, 2b – 3) = (4, –5)

Answer : Since, the ordered pairs are equal, the corresponding elements are equal.

∴, a + 3 = 5 …(i) and b – 2 = 1 …(ii)

Solving eq. (i), we get a + 3 = 5

⇒ a = 5 – 3

⇒ a = 2

Solving eq. (ii), we get b – 2 = 1

⇒ b = 1 + 2

⇒ b = 3

Hence, the value of a = 2 and b = 3.

  • Since, the ordered pairs are equal, the corresponding elements are

∴, a + b = 4 …(i) and 2b – 3 = -5 …(ii) Solving eq. (ii), we get

2b – 3 = -5

⇒ 2b = -5 + 3

⇒ 2b = -2

⇒ b = -1

 

Putting the value of b = – 1 in eq. (i), we get a + (-1) = 4

⇒ a – 1 = 4

⇒ a = 4 + 1

⇒ a = 5

Hence, the value of a = 5 and b = -1.