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Home » For a transistor, αdc and βdc are the current ratios, then the value of  is
For a transistor, αdc and βdc are the current ratios, then the value of \frac{{{\beta }_{dc}}-{{\alpha }_{dc}}}{{{\alpha }_{dc}}.{{\beta }_{dc}}} is
Physics | Physics
For a transistor, αdc and βdc are the current ratios, then the value of \frac{{{\beta }_{dc}}-{{\alpha }_{dc}}}{{{\alpha }_{dc}}.{{\beta }_{dc}}} is
  1. 1
  2. 1.5
  3. 2
  4. 2.5

Solution: the correct answer is A. 1

\frac{{{\beta }_{dc}}-{{\alpha }_{dc}}}{{{\alpha }_{dc}}.{{\beta }_{dc}}}=\frac{\frac{\alpha }{1-\alpha }-\alpha }{\frac{\alpha }{1-\alpha }\times \alpha }=\frac{{{\alpha }^{2}}}{{{\alpha }^{2}}}

\frac{{{\beta }_{dc}}-{{\alpha }_{dc}}}{{{\alpha }_{dc}}.{{\beta }_{dc}}}=1

i

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