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Home » From the following data, find: (i) Median (ii) Upper quartile 25, 10, 40, 88, 45, 60, 77, 36, 18, 95, 56, 65, 7, 0, 38 and 83
From the following data, find:
(i) Median
(ii) Upper quartile
25, 10, 40, 88, 45, 60, 77, 36, 18, 95, 56, 65, 7, 0, 38 and 83
Class 10 | ICSE | Maths | Measures of Central Tendency | Selina
From the following data, find:
(i) Median
(ii) Upper quartile
25, 10, 40, 88, 45, 60, 77, 36, 18, 95, 56, 65, 7, 0, 38 and 83

Solution:
Arrange the data given in ascending order
0,7,10,18,25,36,38,40,45,56,60,65,77,83,88,95

(i) Median is the mean of 8^{\text {th }} and 9^{\text {th }} term
Therefore, median =(40+45) / 2=85 / 2=42.5

(ii) Upper quartile =
\begin{array}{l} q_{3}=\left(\frac{3(n)}{4}\right)^{\text {th }} \text { term } \\ q_{3}=\frac{3 \times 16^{t h}}{4} \text { term }=12^{\text {th }} \text { term }=65 \end{array}

i

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