XeF2, XeF4 and XeF6 are obtained through direct chemical reactions occurring between Xe and F2. The product of the chemical reaction depends upon the conditions of the reaction: ![\[Xe~(excess)+~{{F}_{2}}\to ~Xe{{F}_{2}}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-e14844619c107dad35b9476d3dfad36a_l3.png "Rendered by QuickLaTeX.com")
When Xe reacts with F2 under the condition of 673K temperature and 1 bar pressure, XeF2 is produced.
![\[Xe~+~2{{F}_{2}}\to ~Xe{{F}_{4}}\left( 1:5\text{ }ratio \right)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-6a684776f7763cd69c834655fd6c041b_l3.png "Rendered by QuickLaTeX.com")
When Xe reacts with F2 in the ratio of 1:5 under the condition of 873K temperature and 7 bar pressures, XeF4 is produced.
![\[Xe~+~3{{F}_{2~}}\to ~Xe{{F}_{6}}\left( 1:20\text{ }ratio \right)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-5840cb0089cded69a0e06e6b4c687304_l3.png "Rendered by QuickLaTeX.com")
When Xe reacts with F2 in the ratio of 1:20 under the condition of 573K temperature and 60-70 bar pressures, XeF6 is produced.