Solution:
The number 12 is the first multiple of four that is greater than ten.
The following multiple will be 16.
As a result, the series formed as follows: 12, 16, 20, 24,…
All of these are divisible by 4, hence they are all terms of an A.P. with 12 as the first term and 4 as the common difference.
The residual is 2 when we divide 250 by 4. As a result, 250 2 = 248 is divisible by four.
The current series is as follows:
12, 16, 20, 24, …, 248
Let the nth term of this A.P. be 248.
The first term, a = 12
The common difference, d = 4
an = 248
As we all know,
an = a+(n−1)d
248 = 12+(n-1)×4
236/4 = n-1
59 = n-1
n = 60
As a result, there are 60 multiples of 4 in the range of 10 to 250.