How much heat energy is released when 5.0 g of water at 20C changes into ice at 0C? Take specific heat capacity of water =4.2 J g-1 K-1, specific latent heat of fusion of ice = 336 J g-1.
How much heat energy is released when 5.0 g of water at 20C changes into ice at 0C? Take specific heat capacity of water =4.2 J g-1 K-1, specific latent heat of fusion of ice = 336 J g-1.

Solution:

According to the question, mass of water m is 5.0 g

Specific heat capacity (c) of water is 4.2 J g-1 K-1

Specific latent heat of fusion (L) of ice is 336 J g-1

In order to calculate the heat energy, we will use the following expression –

Q = m × c × (change in temperature)

Therefore, using above expression the amount of heat energy released when 5.0 g of water at 200 C changes into water at 00 C is

= 5 × 4.2 × 20 = 420 J

Similarly, we can write the expression for –

The heat energy released when 5.0 g of water at 0 degrees C changes into ice at 0 degrees C

= 5 × 336 J = 1680 J

Therefore, total amount of heat released = 1680 J + 420 J = 2100 J