Solution:
As per the inquiry,
Stomach muscle = 4 cm,
DE = 6 cm
EF = 9 cm
FD = 12 cm
Too,
∆ABC ∼ ∆DEF
We have,
By taking initial two terms, we have
Also, by taking last two terms, we have,
Presently,
Accordingly, the border of the triangle is 18 cm.