Solution:
18, a, (b – 3) are in AP
⇒ a – 18 = b – 3 – a
⇒ a + a – b = -3 + 18
⇒ 2a – b = 15
If 18, a, (b – 3) are in AP, then find the value of (2a – b)
If 18, a, (b – 3) are in AP, then find the value of (2a – b)
Solution:
18, a, (b – 3) are in AP
⇒ a – 18 = b – 3 – a
⇒ a + a – b = -3 + 18
⇒ 2a – b = 15