If a, b, c and d are in proportion, prove that: (iii)

    \[({{\mathbf{a}}^{\mathbf{4}}}~+\text{ }{{\mathbf{c}}^{\mathbf{4}}}):\text{ }({{\mathbf{b}}^{\mathbf{4}}}~+\text{ }{{\mathbf{d}}^{\mathbf{4}}})\text{ }=\text{ }{{\mathbf{a}}^{\mathbf{2}}}{{\mathbf{c}}^{\mathbf{2}}}:\text{ }{{\mathbf{b}}^{\mathbf{2}}}{{\mathbf{d}}^{\mathbf{2}}}\]

(iv)

    \[\frac{{{a}^{2}}+ab}{{{c}^{2}}+cd}=\frac{{{b}^{2}}-2ab}{{{d}^{2}}-2cd}\]