Solution:-
From the figure, two line segments are intersecting each other at P.
In ΔBCP and ΔDPE
5/10 = 6/12
Dividing LHS and RHS by 2 we get,
½ = ½
Therefore, ΔBCD ~ ΔDEP
If in two right triangles, one of the acute angle of one triangle is equal to an acute angle of the other triangle, can you say that the two triangles are similar? Why?
If in two right triangles, one of the acute angle of one triangle is equal to an acute angle of the other triangle, can you say that the two triangles are similar? Why?