Solution:
k, (2k – 1) and (2k + 1) are the three successive terms of an AP.
(2k – 1) – k = (2k + 1) – (2k – 1)
⇒ 2 (2k – 1) = 2k + 1 + k
⇒ 4k – 2 = 3k + 1
⇒ 4k – 3k = 1 + 2
⇒ k = 3
k = 3
If k, (2k-1) and (2K+1) are the three successive terms of an AP, find the value of k.
If k, (2k-1) and (2K+1) are the three successive terms of an AP, find the value of k.