The correct option is option (c) 
is the midpoint of BC
=> the coordinates of are
![\begin{aligned} &\mathrm{D}\left(\frac{6+1}{2} \cdot \frac{5+4}{2}\right)\left[\mathrm{B}(6,5) \text { and } \mathrm{C}(1,4) \Rightarrow\left(\mathrm{x}_{1}=6, \mathrm{y}_{1}=5\right) \text { and }\left(\mathrm{x}_{2}=1, \mathrm{y}_{2}=4\right)\right] \\ &\text { i.e., } \mathrm{D}\left(\frac{7}{2}, \frac{9}{2}\right) \end{aligned}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-f96d02da6a91d49cfae06af5381e87ff_l3.png "Rendered by QuickLaTeX.com")
If 
and 
be the vertices of 
and 
is a median, then the coordinates of are (a) 
(b) 
(c) (d) none of these
and be the vertices of and is a median, then the coordinates of are (a) (b) (c) (d) none of theseIf and be the vertices of and is a median, then the coordinates of are (a) (b) (c) (d) none of these
and be the vertices of and is a median, then the coordinates of are (a) (b) (c) (d) none of these