If PA and PB are tangents from an outside point P. such that PA = 10 cm and ∠APB = 60°. Find the length of chord AB.
If PA and PB are tangents from an outside point P. such that PA = 10 cm and ∠APB = 60°. Find the length of chord AB.

Given,

AP=10cm

\angle APB={{60}^{\circ }}

According to the figure

We know that,

A line drawn from centre to point from where external tangents are drawn, bisects the angle made by tangents at that particular point

\angle OPB=\angle APO=\frac{1}{2}\times {{60}^{\circ }}={{30}^{\circ }}

And, bisected perpendicularly the chord AB

\therefore AB=2AM

In \vartriangle AMP,

\sin {{30}^{\circ }}=\frac{\text{Opposite}}{\text{Hypotenuse}}=\frac{AM}{AP}

AM=AP\sin {{30}^{\circ }}

\frac{AP}{2}=\frac{10}{2}

 =5cm  [As AB = 2AM]

So, AP=2AM=10cm

And,AB=2AM=10cm