It is given that
(pa + qb): (pc + qd) :: (pa – qb): (pc – qd)
We can write it as
Therefore, it is proved that a: b :: c: d.
It is given that
(pa + qb): (pc + qd) :: (pa – qb): (pc – qd)
We can write it as
Therefore, it is proved that a: b :: c: d.