If $P(A)=1 / 2, P(B)=0$, then $P(A \mid B)$ isA. 0B. ${ }^{1 / 2}$C. not definedD. 1

Home » If , then isA. 0B. C. not definedD. 1

If $P(A)=1 / 2, P(B)=0$ , then $P(A \mid B)$ is
A. 0
B. ${ }^{1 / 2}$
C. not defined
D. 1

CBSE | Maths | NCERT | Probability

If $P(A)=1 / 2, P(B)=0$ , then $P(A \mid B)$ is
A. 0
B. ${ }^{1 / 2}$
C. not defined
D. 1

Answer: C. Not defined

Explanation:

We are aware that, according to the concept of conditional probability,

$\mathrm{P}(\mathrm{A} \mid \mathrm{B})=\frac{\mathrm{P}(\mathrm{A} \cap \mathrm{B})}{\mathrm{P}(\mathrm{B})}$

Given: $\mathrm{P}(\mathrm{A})=1 / 2$

& $\mathrm{P}(\mathrm{B})=0$

Evaluating the value of parameter
$\mathrm{P}(\mathrm{A} \mid \mathrm{B})=\frac{\mathrm{P}(\mathrm{A} \cap \mathrm{B})}{0}=(\mathrm{A} \cap \mathrm{B}) \times \frac{1}{0}$ , which is not defined

i

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