Solution:
Provided that,
a3 = 4 is the 3rd term
and, a9 = −8 is the 9th term
We all know that,
an = a+(n−1)d
Therefore,
a3 = a+(3−1)d
4 = a+2d ……………………………………… (i)
a9 = a+(9−1)d
−8 = a+8d ………………………………………………… (ii)
(ii) – (i), we get,
−12 = 6d
d = −2
From the equation (i), we get,
4 = a+2(−2)
4 = a−4
a = 8
Let nth term of this A.P. be zero.
an = a+(n−1)d
0 = 8+(n−1)(−2)
0 = 8−2n+2
2n = 10
n = 5 As a result, 5th term of the above A.P. is 0.