If the product of the roots of the equation $x^{2}-3 x+k=10$ is $-2$ then the value of $k$ is(a) $-2$(b) $-8$(c) $8$(d) 12

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If the product of the roots of the equation $x^{2}-3 x+k=10$ is $-2$ then the value of $k$ is
(a) $-2$
(b) $-8$
(c) $8$
(d) 12

If the product of the roots of the equation $x^{2}-3 x+k=10$ is $-2$ then the value of $k$ is
(a) $-2$
(b) $-8$
(c) $8$
(d) 12

Answer is (c) 8

It is given that the product of the roots of the equation $x^{2}-3 x+k=10$ is $-2$ The equation can be rewritten as:
$x^{2}-3 x+(k-10)=0$

Product of the roots of a quadratic equation $=\frac{c}{a}$

$\begin{array}{l} \Rightarrow \frac{c}{a}=-2 \\ \Rightarrow \frac{(k-10)}{1}=-2 \\ \Rightarrow k=8 \end{array}$

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