In ∆ABC, DE ║ BC so that AD = (7x – 4) cm, AE = (5x – 2) cm, DB = (3x + 4) cm and EC = 3x cm. Then, we have: (a) x = 3 (b) x = 5 (c) x = 4 (d) x = 2.5
In ∆ABC, DE ║ BC so that AD = (7x – 4) cm, AE = (5x – 2) cm, DB = (3x + 4) cm and EC = 3x cm. Then, we have: (a) x = 3 (b) x = 5 (c) x = 4 (d) x = 2.5

Correct Answer: (c) x = 4

Explanation:

 

 

 

Given,

DE || BC

Applying Thales’ theorem,

\begin{array}{l}  \frac{{AD}}{{BD}} = \frac{{AE}}{{EC}}\\  \frac{{7x-4}}{{3x+4}} = \frac{{5x-2}}{{3x}}\\  \end{array}

3????(7???? − 4) = (5???? − 2)(3???? + 4)

21????2 − 12???? = 15????2 + 20???? − 6???? − 8

21????2 − 12???? = 15????2 + 14???? − 8

6????2 − 26???? + 8 = 0

2 (3????2 − 13???? + 4) = 0

3????2 − 13???? + 4 = 0

3????2 − 12???? − ???? + 4 = 0

3???? (???? − 4) − 1 (???? − 4) = 0

(???? − 4)(3???? − 1) = 0

???? − 4 = 0 ???????? 3???? − 1 = 0

???? − 4 ???????? ???? = 1/3

If ???? = 1/3,

7???? − 4 = −5/3 < 0; ???????? ???????? ???????????? ????????????????????????????????.

Hence, x = 4