Login/Sign Up
Home » In ∆ABC, the bisector of ∠B meets AC at D. A line OQ║AC meets AB, BC and BD at O, Q and R respectively. Show that BP × QR = BQ × PR
In ∆ABC, the bisector of ∠B meets AC at D. A line OQ║AC meets AB, BC and BD at O, Q and R respectively. Show that BP × QR = BQ × PR
CBSE | Class 10 | Exercise 4A | Maths | RS Aggarwal | Triangles
In ∆ABC, the bisector of ∠B meets AC at D. A line OQ║AC meets AB, BC and BD at O, Q and R respectively. Show that BP × QR = BQ × PR

Answer:

 

 

 

In triangle BQO,

BR bisects angle B.

Applying angle bisector theorem,

\begin{array}{l} \frac{{QR}}{{PR}} = \frac{{BQ}}{{BP}}\\ \end{array}

Hence, proved.

i

More Material