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Home » In a ∆ABC, it is given that AD is the internal bisector of ∠A. If AB = 10cm, AC = 14cm and BC = 6cm, then CD = ? (a) 4.8cm (b) 3.5cm (c) 7cm (d) 10.5cm
In a ∆ABC, it is given that AD is the internal bisector of ∠A. If AB = 10cm, AC = 14cm and BC = 6cm, then CD = ? (a) 4.8cm (b) 3.5cm (c) 7cm (d) 10.5cm
CBSE | Class 10 | Exercise MCQ | Maths | RS Aggarwal | Triangles
In a ∆ABC, it is given that AD is the internal bisector of ∠A. If AB = 10cm, AC = 14cm and BC = 6cm, then CD = ? (a) 4.8cm (b) 3.5cm (c) 7cm (d) 10.5cm

Correct Answer: (b) 3.5cm

Explanation:

 

 

 

 

Using angle bisector in ∆ABC,

\begin{array}{l} \frac{{AB}}{{AC}} = \frac{{BD}}{{DC}}\\ \frac{10}{14} = \frac{6-x}{x}\\ \end{array}

10x = 84 – 14x

24x = 84

x = 3.5

i

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