In a p-n junction diode, the current I can be expressed as$I=I_{0} \exp \left(\frac{e V}{2 k_{B} T}-1\right)$where $I_{0}$ is called the reverse saturation current, $V$ is the voltage across the diode and is positive for forward bias and negative for reverse bias, and I is the current through the diode, $k_{B}$ is the Boltzmann constant $\left(8.6 \times 10^{-5} \mathrm{eV} / \mathrm{K}\right)$ and $\mathrm{T}$ is the absolute temperature. If for a given diode $\mathrm{l}_{0}=5$ $\times 10^{-12} \mathrm{~A}$ and $\mathrm{T}=300 \mathrm{~K}$, then(a) What will be the forward current at a forward voltage of $0.6$ V?(b) What will be the increase in the current if the voltage across the diode is increased to $0.7 \mathrm{~V}$ ?

Home » In a p-n junction diode, the current I can be expressed aswhere is called the reverse saturation current, is the voltage across the diode and is positive for forward bias and negative for reverse bias, and I is the current through the diode, is the Boltzmann constant and is the absolute temperature. If for a given diode and , then(a) What will be the forward current at a forward voltage of V?(b) What will be the increase in the current if the voltage across the diode is increased to ?

In a p-n junction diode, the current I can be expressed as
$I=I_{0} \exp \left(\frac{e V}{2 k_{B} T}-1\right)$
where $I_{0}$ is called the reverse saturation current, $V$ is the voltage across the diode and is positive for forward bias and negative for reverse bias, and I is the current through the diode, $k_{B}$ is the Boltzmann constant $\left(8.6 \times 10^{-5} \mathrm{eV} / \mathrm{K}\right)$ and $\mathrm{T}$ is the absolute temperature. If for a given diode $\mathrm{l}_{0}=5$ $\times 10^{-12} \mathrm{~A}$ and $\mathrm{T}=300 \mathrm{~K}$ , then
(a) What will be the forward current at a forward voltage of $0.6$ V?
(b) What will be the increase in the current if the voltage across the diode is increased to $0.7 \mathrm{~V}$ ?

CBSE | Class 12 | NCERT | Physics | Semiconductor Electronics: Materials, Devices and Simple Circuits

In a p-n junction diode, the current I can be expressed as
$I=I_{0} \exp \left(\frac{e V}{2 k_{B} T}-1\right)$
where $I_{0}$ is called the reverse saturation current, $V$ is the voltage across the diode and is positive for forward bias and negative for reverse bias, and I is the current through the diode, $k_{B}$ is the Boltzmann constant $\left(8.6 \times 10^{-5} \mathrm{eV} / \mathrm{K}\right)$ and $\mathrm{T}$ is the absolute temperature. If for a given diode $\mathrm{l}_{0}=5$ $\times 10^{-12} \mathrm{~A}$ and $\mathrm{T}=300 \mathrm{~K}$ , then
(a) What will be the forward current at a forward voltage of $0.6$ V?
(b) What will be the increase in the current if the voltage across the diode is increased to $0.7 \mathrm{~V}$ ?

The expression for current in a p-n junction diode, is given as

$I=I_{0} \exp \left(\frac{e V}{2 k_{B} T}-1\right)$

Here, $l_{0}=5 \times 10^{-12} \mathrm{~A}$

$\mathrm{T}=300 \mathrm{~K}$

$\mathrm{k}_{\mathrm{B}}$ is the Boltzmann constant with a value of $8.6 \times 10^{-5} \mathrm{eV} / \mathrm{k}=8.6 \times 10^{-5} \times 1.6 \times 10^{-19}=1.376 \times 10^{-23} \mathrm{~J} / \mathrm{K}$