In a T.T. match between Geeta and Ritu, the probability of the winning of Ritu is

    \[\mathbf{0}.\mathbf{73}\]

. Find the probability of:

    \[\left( \mathbf{i} \right)\]

winning of Geeta

    \[\left( \mathbf{ii} \right)\]

not winning of Ritu
In a T.T. match between Geeta and Ritu, the probability of the winning of Ritu is

    \[\mathbf{0}.\mathbf{73}\]

. Find the probability of:

    \[\left( \mathbf{i} \right)\]

winning of Geeta

    \[\left( \mathbf{ii} \right)\]

not winning of Ritu

Solution:

    \[\left( i \right)\]

Winning of Geeta is a complementary event to winning of Ritu

Thus,

P(winning of Ritu)

    \[+\]

P(winning of Geeta)

    \[=\text{ }1\]

P(winning of Geeta)

    \[=\text{ }1\text{ }\text{ }P\]

(winning of Ritu)

P(winning of Geeta)

    \[=\text{ }1~~0.73\]

P(winning of Geeta

    \[)\text{ }=\text{ }0.27\]

    \[\left( ii \right)~\]

 Not winning of Ritu is a complementary event to winning of Ritu

Thus,

P(winning of Ritu)

    \[+\]

P(not winning of Ritu

    \[)\text{ }=\text{ }1\]

P(not winning of Ritu)

    \[=\text{ }1\text{ }\text{ }P\]

(winning of Ritu)

P(not winning of Ritu)

    \[=\text{ }1~~0.73\]

P(not winning of Ritu)

    \[=\text{ }0.27\]