Solution:
Suppose that a is the first term and d is the common difference, then we have:
Here, a = 2, l = 29 and Sn = 155
We know that: l = a + (n-1)d (1)
(n – 1)d = 29 – 2 = 27
Therefore, 29 = 2 + (10 – 1)d = 2 + 9d
9d = 27
Thus, d = 3
In an AP, the first term is 2, the last term is 29 and the sum of all the terms is 155. Find the common difference.
In an AP, the first term is 2, the last term is 29 and the sum of all the terms is 155. Find the common difference.