In an experiment, 17 g of ice is used to bring down the temperature of 40 g of water at 34oC to its freezing temperature. The specific heat capacity of water is 4.2 J g-1 K-1. Calculate the specific latent heat of ice. State one important assumption made in the above calculation.
In an experiment, 17 g of ice is used to bring down the temperature of 40 g of water at 34oC to its freezing temperature. The specific heat capacity of water is 4.2 J g-1 K-1. Calculate the specific latent heat of ice. State one important assumption made in the above calculation.

Solution:

According to the question Mass of ice (m1) is 17 g

Mass of water m2 is 40 g

Change in temperature is given by

34 – 0 = 34 K

We know that the specific heat capacity of water is 4.2 J g-1 K-1

Heat energy gained by ice (latent heat of ice), Q = heat energy released by water, assuming no heat loss. Using the below expression for heat energy,

Q = m × c × (Change in temperature)

Upon substituting values, we get => Q = 40 × 34 × 4.2

Q = 5712 J

Expression for the specific latent heat of ice is

L = Q / m = 5712 / 17

Therefore, L = 336 J g-1

Assumption : There is no loss of energy to the surroundingd.