In an isosceles ∆ABC, if AC = BC and $A{B^2} = 2A{C^2}$, then ∠C = ? (a) ${30^0}$ (b) ${45^0}$ (c) ${60^0}$ (d) ${90^0}$

Home » In an isosceles ∆ABC, if AC = BC and , then ∠C = ? (a) (b) (c) (d)

In an isosceles ∆ABC, if AC = BC and $A{B^2} = 2A{C^2}$ , then ∠C = ? (a) ${30^0}$ (b) ${45^0}$ (c) ${60^0}$ (d) ${90^0}$

In an isosceles ∆ABC, if AC = BC and $A{B^2} = 2A{C^2}$ , then ∠C = ? (a) ${30^0}$ (b) ${45^0}$ (c) ${60^0}$ (d) ${90^0}$

Correct Answer: (d) ${90^0}$

Explanation:

Given,

AC = BC

????????² = 2????????² = ????????² + ????????² = ????????² + ????????²

Applying Pythagoras theorem,

∆ABC is right angled at C

∠???? = ${90^0}$

i

Sign up now and study all subjects for free