Solution:
Given,
ΔACB ∼ ΔAPQ
, , and
To find: CA and AQ
ΔACB ∼ ΔAPQ [given]
BA/ AQ = CA/ AP = BC/ PQ
(Corresponding Parts of Similar Triangles)
=
Similarly,
CA/ AP = BC/ PQ
and
Solution:
Given,
ΔACB ∼ ΔAPQ
, , and
To find: CA and AQ
ΔACB ∼ ΔAPQ [given]
BA/ AQ = CA/ AP = BC/ PQ
(Corresponding Parts of Similar Triangles)
=
Similarly,
CA/ AP = BC/ PQ
and