Solution: In the F2 progeny, the characters are RrYy x RrYy
So, the cross will be-
RY | Ry | rY | ry | |
RY | RRYY Round and yellow | RRYy Round and yellow | RrYY Round and yellow | RrYy Round and yellow |
Ry | RRYy Round and yellow | RRyy Round and green | RrYy Round and yellow | Rryy Round and green |
rY | RrYY Round and yellow | RrYy Round and yellow | rrYY Wrinkled and yellow | rrYy Wrinkled and yellow |
ry | RrYy Round and yellow | Rryy Round and green | rrYy Wrinkled and yellow | rryy Wrinkled and green |
So, the phenotypic ratio is-
Round yellow — 9
(ii) Round green — 3
(iii) Wrinkled yellow — 3
(iv) Wrinkled green — 1
9 : 3 : 3: 1