Solution:-
From the question it is given that,
AB||DE
AC = 3 cm
CE = 7.5 cm
BD = 14 cm
From the figure,
∠ACB = ∠DCE [because vertically opposite angles]
∠BAC = ∠CED [alternate angles]
Then, ∆ABC ~ ∆CDE
So, AC/CE = BC/CD
3/7.5 = BC/CD
By cross multiplication we get,
7.5BC = 3CD
Let us assume BC = x and CD = 14 – x
7.5 × x = 3 × (14 – x)
7.5x = 42 – 3x
7.5x + 3x = 42
10.5x = 42
x = 42/10.5
x = 4
Therefore, BC = x = 4 cm
CD = 14 – x
= 14 – 4
= 10 cm