Solution:-

From the figure, AF, BE and CD are parallel lines.

Consider the ∆AEF and ∆CED

∠AEF and ∠CED [because vertically opposite angles are equal]

∠F = ∠C [alternate angles are equal]

Therefore, ∆AEF ~ ∆CED

So, AF/CD = AE/ED

7.5/4.5 = y/3

By cross multiplication,

y = (7.5 × 3)/4.5

y = 5 cm

So, similarly in ∆ACD, BE ||CD

Therefore, ∆ABE ~ ∆ACD

EB/CD = AE/AD

x/CD = y/y + 3

x/4.5 = 5/(5 + 3)

x/4.5 = 5/8

x = (4.5 × 5)/8

x = 22.5/8

x = 225/80

x = 45/16

x =