Solution:
According to the given question, it’s clear that
In cyclic quadrilateral
![\[ABCD,\text{ }DC\text{ }||\text{ }AB\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-03b5f05688dccda0154b6085a3daec0f_l3.png "Rendered by QuickLaTeX.com")
And given,
![\[\angle DAB\text{ }=\text{ }{{105}^{o}}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-fea2920f6e443fa4a093917d3218ecd4_l3.png "Rendered by QuickLaTeX.com")
(i) Hence,
![\[\angle BCD\text{ }=\text{ }{{180}^{o}}-\text{ }{{105}^{o}}~=\text{ }{{75}^{o}}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-5254caf1fecf34317fbb34c374b355e3_l3.png "Rendered by QuickLaTeX.com")
[Sum of opposite angles in a cyclic quadrilateral is 180o]
(ii) So,
![\[\angle ADC\text{ }and\angle DAB\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-2c5c26d607cb44fa24742b9f1f4a08b5_l3.png "Rendered by QuickLaTeX.com")
are corresponding angles.
Thus,
![\[\angle ADC\text{ }+\angle DAB\text{ }=\text{ }{{180}^{o}}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-046d5b7f7e2fdfc67d09dafcaf20c36c_l3.png "Rendered by QuickLaTeX.com")
![\[\angle ADC\text{ }=\text{ }{{180}^{o}}-\text{ }{{105}^{o}}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-1af17dd0c600e8fcaa5acd1476fff6d6_l3.png "Rendered by QuickLaTeX.com")
Hence,
![\[\angle ADC\text{ }=\text{ }{{75}^{o}}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-afe7b05ce85e7732b63817bc5ee099dd_l3.png "Rendered by QuickLaTeX.com")
and 
, internal resistance 
and 
, connected in parallel. The equivalent emf of the combination is- (A) 
(B) 
(C) 
(D) 
and 
are collinear, prove that 
and 
be three points such that area of a 
is 4 sq units, find the value of 
. for which the area of a ABC having vertices 
and 
is 35 sq units. for which the points 
and 
are collinear. for which the points 
and 
are collinear. for which the points 
and 
are collinear.
and 