In the given figure, a diode D is connected to an external resistance R=100 \Omega and an e.m.f. of 3.5 \mathrm{~V}. If the barrier potential developed across the diode is 0.5 \mathrm{~V}, the current in the circuit will be: (1) 35 \mathrm{~mA} (2) 30 \mathrm{~mA} (3) 40 \mathrm{~mA} (4) 20 \mathrm{~mA}
In the given figure, a diode D is connected to an external resistance R=100 \Omega and an e.m.f. of 3.5 \mathrm{~V}. If the barrier potential developed across the diode is 0.5 \mathrm{~V}, the current in the circuit will be: (1) 35 \mathrm{~mA} (2) 30 \mathrm{~mA} (3) 40 \mathrm{~mA} (4) 20 \mathrm{~mA}

The correct Solution is (2)
\begin{array}{l} \text { Current }=\frac{(3.5-0.5)}{100} \mathrm{~A} \\ =\frac{3}{100} \mathrm{~A}=30 \mathrm{~mA} \end{array}