Login/Sign Up
Home » In the given figure, DE║BC such that AD = x cm, DB = (3x + 4) cm, AE = (x + 3) cm and EC = (3x + 19) cm. Find the value of x.
In the given figure, DE║BC such that AD = x cm, DB = (3x + 4) cm, AE = (x + 3) cm and EC = (3x + 19) cm. Find the value of x.
CBSE | Class 10 | Exercise-Formative Assessment | Maths | RS Aggarwal | Triangles
In the given figure, DE║BC such that AD = x cm, DB = (3x + 4) cm, AE = (x + 3) cm and EC = (3x + 19) cm. Find the value of x.

Answer:

 

 

 

DE || BC

\begin{array}{l} \frac{{AD}}{{DB}} = \frac{{AE}}{{EC}}\\ \frac{x}{3x+4} = \frac{x+3}{{3x+19}}\\ \end{array}

???? (3???? + 19) = (???? + 3)(3???? + 4)

3????2 + 19???? = 3????2 + 4???? + 9???? + 12

19???? − 13???? = 12

6x = 12

???? = 2

i

More Material