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Home » In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is: (1) 5/27 (2) 4/9 (3) 9/4 (4) 27/5
In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is:
(1) 5/27
(2) 4/9
(3) 9/4
(4) 27/5
Physics | Physics
In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is:
(1) 5/27
(2) 4/9
(3) 9/4
(4) 27/5

In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the
Balmer series is:

\begin{array}{l} \frac{1}{\lambda_{1}}=\mathrm{R}_{\mathrm{e}}\left(\frac{1}{1^{2}}-\frac{1}{2^{2}}\right) \\ \frac{1}{\lambda_{2}}=\mathrm{R}_{\mathrm{e}}\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right) \\ \frac{\lambda_{1}}{\lambda_{2}}=\frac{5}{27} \end{array}

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