Is the area of the circle inscribed in a square of side a cm,

    \[{{a}^{2}}\]

    \[c{{m}^{2}}\]

? Give reasons for your answer.
Is the area of the circle inscribed in a square of side a cm,

    \[{{a}^{2}}\]

    \[c{{m}^{2}}\]

? Give reasons for your answer.

The given statement is false

Explanation:

Let  us assume a be the side of square.

From the question we got  that the circle is inscribed in the square.

Therefore, Diameter of circle = Side of square = a

Then Radius of the circle =

    \[a/2\]

Now we got Area of the circle =

    \[\pi {{r}^{2}}=\pi {{(a/2)}^{2}}=(\pi {{a}^{2}})/4\]

    \[c{{m}^{2}}\]

Therefore, area of the circle is

    \[(\pi {{a}^{2}})/4\]

    \[c{{m}^{2}}\]

Therefore the area of the circle inscribed in a square of side a cm is not

    \[{{a}^{2}}\]

 

    \[c{{m}^{2}}\]