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It is given that ∆ABC~∆PQR and \begin{array}{l} \frac{{BC}}{{QR}} = \frac{2}{3}\\ \end{array}, then \frac{{ar(\Delta PQR)}}{{ar(\Delta ABC)}} = ? (a)\frac{2}{3}(b)\frac{3}{2}(c)\frac{4}{9}(d)\frac{9}{4}
CBSE | Class 10 | Exercise MCQ | Maths | RS Aggarwal | Triangles
It is given that ∆ABC~∆PQR and \begin{array}{l} \frac{{BC}}{{QR}} = \frac{2}{3}\\ \end{array}, then \frac{{ar(\Delta PQR)}}{{ar(\Delta ABC)}} = ? (a)\frac{2}{3}(b)\frac{3}{2}(c)\frac{4}{9}(d)\frac{9}{4}

Correct Answer: (d)\frac{9}{4}<strong>Explanation:</strong> Given, ∆ABC ~ ∆PQR\begin{array}{l}

\frac{{BC}}{{QR}} = \frac{2}{3}\\

\end{array}\begin{array}{l}

\frac{{ar(\Delta PQR)}}{{ar(\Delta ABC)}} = \frac{{Q{R^2}}}{{B{C^2}}}\\

=  > {\left( {\frac{3}{2}} \right)^2}\\

=  > \frac{9}{4}

\end{array}$

i

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