It is given that the probability that A can solve a given problem is \frac{3}{5} and the probability that B can solve the same problem is \frac{2}{3}. The probability that at least one of A and B can solve a problem is
A. \frac{2}{5}
B. \frac{1}{15}
C. \frac{13}{15}
D. \frac{2}{15}
It is given that the probability that A can solve a given problem is \frac{3}{5} and the probability that B can solve the same problem is \frac{2}{3}. The probability that at least one of A and B can solve a problem is
A. \frac{2}{5}
B. \frac{1}{15}
C. \frac{13}{15}
D. \frac{2}{15}

\mathrm{P}(\mathrm{A})= probability that A can solve the problem
=3 / 5
And P(B)= probability that B can solve the problem =2 / 3
P(A \cup B)=P(A)+P(B), As the events are independent
\Rightarrow P(A \cap B)=P(A) \cdot P(B)
Thus,
\Rightarrow \mathrm{P}(\mathrm{A})+\mathrm{P}(\mathrm{B})=3 / 5+2 / 3-2 / 5=13 / 15
Hence, correct option is c.