Solution:
(i) The elements of this set are divisors of 6 as well as natural number. As a result, (i) matches with (c).
(ii) Here 2 and 3 are the prime numbers which are also the divisors of 6. As a result, (ii) matches with (a).
Match each of the set on the left in the roster form with the same set on the right described in set-builder form: (i) {1, 2, 3, 6} (a) {
is a prime number and a divisor of 6} (ii) {2, 3} (b) { is an odd natural number less than 10}
is a prime number and a divisor of 6} (ii) {2, 3} (b) { is an odd natural number less than 10}