Answer:
Naman pulls in the string at the rate of 5 cm per second.
Hence, after 12 seconds the length of the string he will pulled is given by:
12 × 5 = 60 cm or 0.6 m
In ∆BMC
By using Pythagoras theorem,
????????2 = ????????2 + ????????2 => (2.4) 2 + (1.8) 2 => 9
∴ BC = 3 m
BC’ = BC – 0.6
=> 3 – 0.6
=> 2.4 m
In ∆BC’M
By using Pythagoras theorem,
????′????2 = ????????′2 − ????????2
=> (2.4) 2 − (1.8) 2
=> 2.52
∴ C’M = 1.6 m
The horizontal distance of the fly from him after 12 seconds is given by:
C’A = C’M + MA
=> 1.6 + 1.2
=> 2.8 m