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Home » P (-3, 2) is the mid-point of line segment AB as shown in the given figure. Find the co-ordinates of points A and B.
P (-3, 2) is the mid-point of line segment AB as shown in the given figure. Find the co-ordinates of points A and B.
Class 10 | Exercise 13B | ICSE | Maths | Section and Mid-Point Formula | Selina
P (-3, 2) is the mid-point of line segment AB as shown in the given figure. Find the co-ordinates of points A and B.

Selina Solutions Concise Class 10 Maths Chapter 13 ex. 13(B) - 4

We know that,

Point A lies on y-axis, so its co-ordinates are 

    \[\left( 0,\text{ }y \right).\]

Point B lies on x-axis, so its co-ordinates are taken to be

    \[\left( x,\text{ }0 \right).\]

    \[P\text{ }\left( -3,\text{ }2 \right)\]

is the mid-point of line segment

    \[AB.\]

So, using mid-point section :

    \[\left( -3,\text{ }2 \right)\text{ }=\text{ }\left( 0+x/2,\text{ }y+0/2 \right)\]

    \[\left( -3,\text{ }2 \right)\text{ }=\text{ }\left( x/2,\text{ }y/2 \right)\]

    \[-3\text{ }=\text{ }x/2\text{ } and \text{ }2\text{ }=\text{ }y/2\]

    \[x\text{ }=\text{ }-6\text{ } and \text{ }y\text{ }=\text{ }4\]

The co-ordinates of point

    \[A\text{ }and\text{ }B\text{ }are \text{ }\left( 0,\text{ }4\right)\text{ }and \text{ }\left( -6,\text{ }0 \right)\]

respectively.

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