Sketch the graphs of the following trigonometric functions: (i) ψ (x) = cos (3x) (ii) u (x) = cos2 x/2
Sketch the graphs of the following trigonometric functions: (i) ψ (x) = cos (3x) (ii) u (x) = cos2 x/2

    \[\left( \mathbf{i} \right)~\psi \text{ }\left( x \right)\text{ }=\text{ }cos\text{ }\left( 3x \right)\]

Since,

    \[f\text{ }\left( x \right)\text{ }=\text{ }cos\text{ }x\]

is a periodic function with period

    \[2\pi .\]

Therefore,

    \[\psi \text{ }\left( x \right)\text{ }=\text{ }cos\text{ }\left( 3x \right)\]

is a periodic function with period

    \[2\pi /3.\]

Hence, we draw the graph of

    \[\psi \text{ }\left( x \right)\text{ }=\text{ }cos\text{ }\left( 3x \right)\]

in the interval

    \[\left[ 0,\text{ }2\pi /3 \right].\]

The values of

    \[\psi \text{ }\left( x \right)\text{ }=\text{ }cos\text{ }\left( 3x \right)\]

at various points in

    \[\left[ 0,\text{ }2\pi /3 \right]\]

are listed below:

The curve is:

RD Sharma Solutions for Class 11 Maths Chapter 6 – Graphs of Trigonometric Functions image -17

    \[\left( \mathbf{ii} \right)~u\text{ }\left( x \right)\text{ }=\text{ }co{{s}^{2}}~x/2\]

Since,

    \[f\text{ }\left( x \right)\text{ }=\text{ }cos\text{ }x\]

is a periodic function with period

    \[2\pi .\]

Therefore,

    \[u\text{ }\left( x \right)\text{ }=\text{ }co{{s}^{2}}~\left( x/2 \right)\]

is a periodic function with period

    \[\pi .\]

Hence, we draw the graph of

    \[u\text{ }\left( x \right)\text{ }=\text{ }co{{s}^{2}}~\left( x/2 \right)\]

in the interval

    \[\left[ 0,\text{ }\pi  \right].\]

The values of

    \[u\text{ }\left( x \right)\text{ }=\text{ }co{{s}^{2}}~\left( x/2 \right)\]

at various points in

    \[\left[ 0,\text{ }\pi  \right]\]

are listed below:

The curve is:

RD Sharma Solutions for Class 11 Maths Chapter 6 – Graphs of Trigonometric Functions image -18