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Solve each of the following system of equations in R – 3x – 6 > 0, 2x – 5 > 0
CBSE | Class 11 | Exercise 15.2 | Linear Inequations | Maths | RD Sharma
Solve each of the following system of equations in R – 3x – 6 > 0, 2x – 5 > 0

3 x-6>0 and 2 x-5>0

3 x-6>0

3 x-6+6>0+6

3 x>6

Dividing both the sides by 3 we get,

3 x / 3>6 / 3

x>2

\therefore \mathrm{x} \in(2, \infty) \ldots(1)

Now,

2 x-5>0

2 x-5+5>0+5

2 x>5

Dividing both the sides by 2 we get,

2 \mathrm{x} / 2>5 / 2

x>5 / 2

\therefore \mathrm{X} \in(5 / 2, \infty) \ldots(2)

From (1) and (2), we get

x \in(2, \infty) \cap(5 / 2, \infty)

\mathrm{x} \in(5 / 2, \infty)

\therefore The solution of the given system of inequations is (5 / 2, \infty).

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