Solution:
From the first eq., write y in terms of 
Substituting different values of in eq.(i) to get different values of 
For 
For 
For 
Therefore, the table for the first eq. 
) is
![\[\begin{tabular}{|r|r|r|r|} \hline $\mathrm{x}$ & $-5$ & 1 & 4 \\ \hline $\mathrm{y}$ & 1 & 5 & 7 \\ \hline \end{tabular}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-4d88296e670e0e08ac44cd4f4288fe3d_l3.png "Rendered by QuickLaTeX.com")
Now, plot the points 
and 
on a graph paper and join 
and 
to get the graph of 
From the second eq., write y in terms of
Substituting different values of in eq.(ii) to get different values of y
For 
For 
For 
Therefore, the table for the second equation 
is
![\[\begin{tabular}{|r|c|c|r|} \hline $\mathrm{x}$ & $-4$ & $-2$ & 0 \\ \hline $\mathrm{y}$ & 0 & 3 & 6 \\ \hline \end{tabular}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-3d0a146ac4ffa416611cb856c28498ec_l3.png "Rendered by QuickLaTeX.com")
Now, plot the points 
and 
on the same graph paper and join 
and 
to get the graph of 
.
It is clear from the graph that, the given lines intersect at 
.
Hence, the solution of the given system of equation is .