Suppose that

    \[6%\]

of the people with blood group O are left-handed and

    \[10%\]

of those with other blood groups are left-handed

    \[30%\]

of the people have blood group O. If a left-handed person is selected at random, what is the probability that he/she will have blood group O?
Suppose that

    \[6%\]

of the people with blood group O are left-handed and

    \[10%\]

of those with other blood groups are left-handed

    \[30%\]

of the people have blood group O. If a left-handed person is selected at random, what is the probability that he/she will have blood group O?

Let’s assume

    \[{{E}_{1}}\]

 = The event that a person selected is of blood group O

    \[{{E}_{2}}\]

 = The event that the people selected is of other group

And H = The event that selected person is left handed

Now,

    \[P({{E}_{1}})\text{ }=\text{ }0.30\]

and

    \[P({{E}_{2}})\text{ }=\text{ }0.70\]

Further,

    \[P(H/{{E}_{1}})\text{ }=\text{ }0.06\]

and

    \[P(H/{{E}_{2}})\text{ }=\text{ }0.10\]

Using Baye’s Theorem, we have

Therefore, the required probability is

    \[9/44\]

.