Solution;
Sum of angles of a quadrilateral = 360°
Let d= 10
The first number be a, then the four numbers will be
a, a + 10, a + 20, a + 30
a + a + 10 + a + 20 + a + 30 = 360
4a + 60 = 360
4a = 360 – 60 = 300
Angles will be 75°, 85°, 95°, 105°
The angles of quadrilateral are in whose AP common difference is 10 degrees . Find the angles.
The angles of quadrilateral are in whose AP common difference is 10 degrees . Find the angles.