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Home » The corresponding sides of two similar triangles are in the ratio 2: 3. If the area of the smaller triangle is 48, find the area of the larger triangle
The corresponding sides of two similar triangles are in the ratio 2: 3. If the area of the smaller triangle is 48c{m^2}, find the area of the larger triangle
CBSE | Class 10 | Exercise-Formative Assessment | Maths | RS Aggarwal | Triangles
The corresponding sides of two similar triangles are in the ratio 2: 3. If the area of the smaller triangle is 48c{m^2}, find the area of the larger triangle

Answer:

Given,

The triangles are similar and the ratio of areas of similar triangles will be equal to the ratio of squares of their corresponding sides.

\begin{array}{l} \frac{{48}}{{Area\ of\ larger\ triangle}} = \frac{{2{}^2}}{{{3^2}}}\\ \frac{{48}}{{Area\ of\ larger\ triangle}} = \frac{4}{9}\\ Area\ of\ larger\ triangle = \frac{{48 \times 9}}{4} = > 108c{m^2} \end{array}

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