![\[\begin{array}{c} \text { Speed of revolution }=30 \mathrm{Km} / \mathrm{s} \\ =3 \times 10^{4} \mathrm{~m} / \mathrm{s} \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-4c86f55151bc875d4dd5fd3b860d57c9_l3.png "Rendered by QuickLaTeX.com")
Time of revolution 
One year 
days (convert into seconds)
![\[=365 \times 24 \times 60 \times 60=3.5 \times 10^{7} \text { seconds }\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-9913d7fe07204fd67bf6ec3c8c96838f_l3.png "Rendered by QuickLaTeX.com")
The formula of radial acceleration:
![\[\mathrm{ac}=\mathrm{V}^{2} / \mathrm{r}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-7e1f020cae364266a0e2726eab1bee3e_l3.png "Rendered by QuickLaTeX.com")
Distance covered by the earth around the sun will be equal to the circumference of orbit.
![\[\begin{array}{l} \text { Speed } \times \text { Time }(\mathrm{V} \cdot \mathrm{T})=2 \pi \mathrm{r} \\ \mathrm{r}=\mathrm{V} \cdot \mathrm{T} / 2 \pi \\ \mathrm{a}_{\mathrm{c}}=\mathrm{V}^{2} / \mathrm{r}=\mathrm{V}^{2} \times 2 \pi / \mathrm{V} \times \mathrm{T} \\ \mathrm{a}_{\mathrm{c}}=2 \pi \mathrm{V} / \mathrm{T} \\ a_{c}=\frac{2 \times 3.14 \times 3 \times 10^{4}}{3.5 \times 10^{7}} \\ \left.\$ \$ \mathrm{a}_{-} \mathbf{c}=\mathbf{5} \cdot 98 \times 10^{\wedge} \mathrm{\{}-3\right\} \mathrm{m} / \mathrm{s}^{\wedge} \mathbf{2} \$ \$ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-5638102b540e68558374a0c03702b255_l3.png "Rendered by QuickLaTeX.com")
The earth revolves around the sun in a circular path with a speed of 
. What is the radial acceleration directed towards the sun?
. What is the radial acceleration directed towards the sun?The earth revolves around the sun in a circular path with a speed of . What is the radial acceleration directed towards the sun?
. What is the radial acceleration directed towards the sun?
.
)
west of the geographic north. The north tip of the magnetic needle of a dip circle placed in the plane of magnetic meridian points above the horizontal. The horizontal component of the earth’s field is measured to be 
Specify the direction and magnitude of the earth’s field at the location.At a certain location in Africa, a compass points 
and 
carrying currents of 
and 
in the same direction are separated by a distance of 
. Estimate the force on a 
section of wire A.
wire carrying a current of 
is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 
. What is the magnetic force on the wire?
and making an angle of 
with the direction of a uniform magnetic field of 
. What is the magnitude of the field 
at a point 
from the wire?
-turns carrying current 
.
is at distance 
from the wire. Find the force acting on the electron if its velocity is directed towards the wire.