What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 \mathrm{~A} and making an angle of 30^{\circ} with the direction of a uniform magnetic field of 0.15 \mathrm{~T} ?
What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 \mathrm{~A} and making an angle of 30^{\circ} with the direction of a uniform magnetic field of 0.15 \mathrm{~T} ?

Ans: We are given the following:
Current in the wire, I=8 \mathrm{~A}
Magnitude of the uniform magnetic field, B=0.15 \mathrm{~T}
Angle between the wire and magnetic field, \theta=30^{\circ}
Magnetic force per unit length on the wire is given as:
f=B \mid \sin \theta \Rightarrow f=0.15 \times 8 \times 1 \times \sin 30^{\circ} \Rightarrow f=0.6 \mathrm{Nm}^{-1}
Therefore, the magnetic force per unit length on the wire is found to be 0.6 \mathrm{~N} \mathrm{~m}^{-1}.